import arviz as az
import numpy as np
import pandas as pd
import pymc as pm
import matplotlib.pyplot as plt

8. Prediction*#

We previously covered Bayesian prediction in Unit 4, Lesson 13. Recall that the core of Bayesian prediction is the posterior predictive distribution

\[ f(x_{n+1}\vert x_{1} , \cdots , x_{n}) = \int_{\Theta}f(x_{n+1} \vert \mathbf{\theta})\pi(\theta \vert x_{1} , \cdots , x_{n})d\theta \]

Think of this as a “weighted average” of the likelihood for new data, with “weights” prescribed by for \(\pi(\theta \vert x_{1} , \cdots , x_{n})\). This is a departure from the “plug-in predictions” you may have encountered in a frequentist course. The result is a distribution of predictions. It should be clear by now that analytical methods are often intractible, and that is no different for the posterior predictive distribution. Fortunately, pymc has some tools that make this easier.

Taste of Cheese*#

Adapted from Unit 6: cheese.odc.

The link in the original .odc file is dead. I downloaded the data from here and have a copy here.

Problem Statement#

As cheddar cheese matures, a variety of chemical processes take place. The taste of matured cheese is related to the concentration of several chemicals in the final product. In a study of cheddar cheese from the Latrobe Valley of Victoria, Australia, samples of cheese were analyzed for their chemical composition and were subjected to taste tests. Overall taste scores were obtained by combining the scores from several tasters.

Can the score be predicted well by the predictors: Acetic, H2S, and Lactic?

data = pd.read_csv("../data/cheese.csv", index_col=0)
X = data[["Acetic", "H2S", "Lactic"]].to_numpy()
# add intercept column to X
X_aug = np.concatenate((np.ones((X.shape[0], 1)), X), axis=1)
y = data["taste"].to_numpy()
data.head(5)
taste Acetic H2S Lactic
1 12.3 4.543 3.135 0.86
2 20.9 5.159 5.043 1.53
3 39.0 5.366 5.438 1.57
4 47.9 5.759 7.496 1.81
5 5.6 4.663 3.807 0.99
with pm.Model() as m:
    # associate data with model (this makes prediction easier)
    X_data = pm.Data("X", X_aug)
    y_data = pm.Data("y", y)

    # priors
    beta = pm.Normal("beta", mu=0, sigma=1000, shape=X.shape[1] + 1)
    tau = pm.Gamma("tau", alpha=0.001, beta=0.001)
    sigma = pm.Deterministic("sigma", 1 / pm.math.sqrt(tau))

    mu = pm.math.dot(X_data, beta)

    # likelihood
    pm.Normal(
        "taste_score",
        mu=mu,
        sigma=sigma,
        observed=y_data,
        shape=X_data.shape[0],
    )

    # start sampling
    trace = pm.sample(5000, target_accept=0.95)
    pm.sample_posterior_predictive(trace, extend_inferencedata=True)
Hide code cell output
Initializing NUTS using jitter+adapt_diag...
Multiprocess sampling (4 chains in 4 jobs)
NUTS: [beta, tau]

Sampling 4 chains for 1_000 tune and 5_000 draw iterations (4_000 + 20_000 draws total) took 11 seconds.
Sampling: [taste_score]

az.summary(trace, hdi_prob=0.95)
mean sd hdi_2.5% hdi_97.5% mcse_mean mcse_sd ess_bulk ess_tail r_hat
beta[0] -28.594 20.567 -68.302 12.992 0.240 0.176 7366.0 9567.0 1.0
beta[1] 0.219 4.635 -8.825 9.345 0.056 0.041 6929.0 8886.0 1.0
beta[2] 3.909 1.283 1.322 6.350 0.014 0.010 8958.0 10953.0 1.0
beta[3] 19.914 8.862 2.569 37.440 0.089 0.069 9970.0 11208.0 1.0
tau 0.010 0.003 0.005 0.015 0.000 0.000 10522.0 10951.0 1.0
sigma 10.446 1.529 7.770 13.536 0.015 0.014 10522.0 10951.0 1.0
y_pred = trace.posterior_predictive.stack(sample=("chain", "draw"))[
    "taste_score"
].values.T
az.r2_score(y, y_pred)
r2        0.577111
r2_std    0.075772
dtype: float64

PyMC may give warnings about the model unless we increase the target_accept parameter of pm.sample. This is because PyMC uses more diagnostics to check if there are any problems with its exploration of the parameter space. Divergences indicate bias in the results.

For further reading, check out Diagnosing Biased Inference with Divergences.

It looks like there are multiple ways to get predictions on out-of-sample data in PyMC. The easiest way is to set up a shared variable using pm.Data in the original model, then using pm.set_data to change to the new observations before calling pm.sample_posterior_predictive.

# single prediction on out-of-sample data
new_obs = np.array([[1.0, 5.0, 7.1, 1.5]])
pm.set_data({"X": new_obs}, model=m)
ppc = pm.sample_posterior_predictive(trace, model=m, predictions=True)
Hide code cell output
Sampling: [taste_score]

The default behavior now is to give one prediction per \(y\)-value. The professor often asks for a single prediction based on the new data; the equivalent here would be to take the mean of the predicted values.

az.summary(ppc.predictions, hdi_prob=0.95)
mean sd hdi_2.5% hdi_97.5% mcse_mean mcse_sd ess_bulk ess_tail r_hat
taste_score[0] 30.055 11.197 8.671 52.698 0.085 0.063 17533.0 17753.0 1.0
%load_ext watermark
%watermark -n -u -v -iv -p pytensor
Last updated: Sun Mar 09 2025

Python implementation: CPython
Python version       : 3.12.7
IPython version      : 8.29.0

pytensor: 2.26.4

pymc      : 5.19.1
numpy     : 1.26.4
arviz     : 0.20.0
matplotlib: 3.9.2
pandas    : 2.2.3